Алгебра 7 класс никольский номер 205

Алгебра 7 класс Никольский. 4.3. Понятие одночлена. Номер №205

Решение а

3ab = 3ba = b3a = ba3 = ab3 = a3b

Решение б

d(−2)3c = d(−2)c3 = d3(−2)c = d3c(−2) = dc(−2)3 = dc3(−2) = −2d3c = −2dc3 = (−2)3dc = (−2)3cd = −2c3d = −2cd3 = c(−2)d3 = c(−2)3d = c3(−2)d = c3d(−2) = cd(−2)3 = cd3(−2) = 3(−2)dc = 3(−2)cd = 3d(−2)c = 3dc(−2) = 3c(−2)d = 3dc(−2)

Решение в

x7yz = x7zy = xy7z = xyz7 = xz7y = xzy7 = 7xyz = 7xzy = 7yxz = 7yzx = 7zxy = 7zyx = yx7z = yxz7 = yzx7 = yz7x = y7xz = y7zx = zx7y = zxy7 = z7xy = z7yx = xy7z = zyx7

Решение г

a4 = 4a

Решение д

ab3 = a3b = ba3 = b3a = 3ab = 3ba

Решение е

2ak5 = 2a5k = 2 * 5ak = 2 * 5ka = 2k5a = 2ka5 = ak5 * 2 = ak2 * 5 = a2k5 = a2 * 5k = a5 * 2k = a5k2 = k2a5 = k2 * 5a = k5 * 2a = k5a2 = ka2 * 5 = ka5 * 2 = 5 * 2ak = 5 * 2ka = 5ka2 = 5k2a = 5a2k = 5ak2

Решение ж

a(−2)bc = a(−2)cb = ac(−2)b = acb(−2) = ab(−2)c = abc(−2) = −2abc = −2acb = −2bac = −2bca = −2cab = −2cba = b(−2)ac = b(−2)ca = bc(−2)c = bac(−2) = bca(−2) = bc(−2)a = c(−2)ab = c(−2)ba = cb(−2)a = cba(−2) = ca(−2)b = cab(−2)

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